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[{"id":2195,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在记录一周内每天的温度变化时,发现某天的气温比前一天上升了5℃,记作+5℃。如果第二天的气温又比这天下降了8℃,那么第二天的气温变化应记作多少?","answer":"B","explanation":"气温下降用负数表示。题目中说明第二天的气温比当天下降了8℃,因此应记作-8℃。选项B正确。其他选项中,A表示上升,C和D是计算错误或混淆了变化方向与数值。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:25:31","updated_at":"2026-01-09 14:25:31","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"+8℃","is_correct":0},{"id":"B","content":"-8℃","is_correct":1},{"id":"C","content":"+3℃","is_correct":0},{"id":"D","content":"-3℃","is_correct":0}]},{"id":1911,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级同学最喜欢的运动项目数据时,制作了如下频数分布表。已知喜欢篮球的人数占总调查人数的30%,且总人数为40人,那么喜欢篮球的学生有多少人?","answer":"B","explanation":"题目考查的是数据的收集、整理与描述中的百分比计算。已知总人数为40人,喜欢篮球的人数占30%,即求40的30%是多少。计算过程为:40 × 30% = 40 × 0.3 = 12(人)。因此,喜欢篮球的学生有12人,正确答案为B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-07 13:11:55","updated_at":"2026-01-07 13:11:55","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10人","is_correct":0},{"id":"B","content":"12人","is_correct":1},{"id":"C","content":"15人","is_correct":0},{"id":"D","content":"18人","is_correct":0}]},{"id":1524,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某校七年级开展‘校园植物分布调查’项目,学生需记录不同区域植物种类数量,并进行数据分析。调查区域被划分为A、B、C三个区域,分别位于平面直角坐标系中的矩形范围内:A区为点(0,0)到(4,3),B区为点(4,0)到(8,3),C区为点(0,3)到(8,6)。已知A区每平方米有2种植物,B区每平方米有3种植物,C区每平方米有1.5种植物。调查过程中发现,B区实际记录的植物种类总数比理论值少6种,而C区比理论值多4种。若三个区域总记录植物种类为86种,求A区的实际面积(单位:平方米)。注:所有区域均为矩形,面积单位为平方米,植物种类数为整数或一位小数。","answer":"解:\n\n第一步:计算各区域的面积。\n\nA区:从(0,0)到(4,3),长为4,宽为3,面积为 4 × 3 = 12(平方米)\nB区:从(4,0)到(8,3),长为4,宽为3,面积为 4 × 3 = 12(平方米)\nC区:从(0,3)到(8,6),长为8,宽为3,面积为 8 × 3 = 24(平方米)\n\n第二步:计算各区域理论植物种类数。\n\nA区理论种类:12 × 2 = 24(种)\nB区理论种类:12 × 3 = 36(种)\nC区理论种类:24 × 1.5 = 36(种)\n\n第三步:设A区实际记录的植物种类为A_actual。\n\n根据题意:\nB区实际 = 36 - 6 = 30(种)\nC区实际 = 36 + 4 = 40(种)\n\n三个区域总记录种类为86种,因此:\nA_actual + 30 + 40 = 86\nA_actual = 86 - 70 = 16(种)\n\n第四步:设A区实际面积为x平方米。\n\n已知A区每平方米有2种植物,因此实际种类数为 2x。\n所以有方程:\n2x = 16\n解得:x = 8\n\n答:A区的实际面积为8平方米。","explanation":"本题综合考查了平面直角坐标系中矩形面积的确定、实数运算、一元一次方程的建立与求解,以及数据的整理与分析能力。解题关键在于理解‘理论值’与‘实际值’的差异,并通过总数量反推未知量。首先利用坐标确定各区域几何尺寸并计算面积,再结合单位面积植物密度求出理论种类数;接着根据题设调整B、C两区的实际记录数,利用总和求出A区实际记录种类;最后设A区实际面积为未知数,建立一元一次方程求解。题目融合了坐标、面积、密度、方程与数据分析,逻辑链条完整,难度较高,适合训练学生综合应用能力。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 12:13:23","updated_at":"2026-01-06 12:13:23","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2553,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"如图,在平面直角坐标系中,点A(2, 3)和点B(6, 3)是抛物线y = ax² + bx + c上的两点,且该抛物线的顶点位于线段AB的垂直平分线上。若该抛物线与x轴有两个交点,则下列结论中正确的是:","answer":"A","explanation":"由题意知,点A(2,3)和点B(6,3)在抛物线上,且它们的纵坐标相同,因此线段AB是水平的。线段AB的中点为((2+6)\/2, (3+3)\/2) = (4, 3)。由于抛物线的顶点在线段AB的垂直平分线上,而AB是水平的,其垂直平分线为竖直线x = 4,因此抛物线的对称轴为x = 4,即顶点横坐标为4,故选项A正确。又因为抛物线与x轴有两个交点,说明判别式Δ > 0,排除D。开口方向无法仅凭两点确定,C项中y轴交点c的值也无法确定,因此B和C不一定成立。综上,唯一必然正确的结论是A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 17:13:46","updated_at":"2026-01-10 17:13:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"抛物线的对称轴为直线x = 4","is_correct":1},{"id":"B","content":"抛物线的开口方向向下","is_correct":0},{"id":"C","content":"抛物线与y轴的交点在y轴正半轴上","is_correct":0},{"id":"D","content":"该抛物线的判别式Δ < 0","is_correct":0}]},{"id":534,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,收集了每位同学每周阅读课外书的小时数,并将数据整理成如下频数分布表:\n\n| 阅读时间(小时) | 0~2 | 2~4 | 4~6 | 6~8 |\n|------------------|------|------|------|------|\n| 人数 | 5 | 12 | 18 | 5 |\n\n若该学生想计算全班同学每周平均阅读时间,他采用每个小组的组中值乘以对应人数,再求和后除以总人数。请问他计算出的平均阅读时间最接近以下哪个值?","answer":"B","explanation":"首先确定每个时间段的组中值:0~2小时的组中值为1,2~4小时为3,4~6小时为5,6~8小时为7。然后计算各组阅读时间总和:1×5=5,3×12=36,5×18=90,7×5=35。总阅读时间为5+36+90+35=166小时。总人数为5+12+18+5=40人。平均阅读时间为166÷40=4.15小时,四舍五入后最接近4.2小时。因此正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:46:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3.8小时","is_correct":0},{"id":"B","content":"4.2小时","is_correct":1},{"id":"C","content":"4.6小时","is_correct":0},{"id":"D","content":"5.0小时","is_correct":0}]},{"id":531,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级数学测验中,老师对全班40名学生的成绩进行了统计,发现成绩在80分及以上的学生占总人数的3\/8。如果成绩在60分到79分之间的学生比80分及以上的多10人,那么成绩低于60分的学生有多少人?","answer":"A","explanation":"首先,全班共有40名学生。成绩在80分及以上的学生占总人数的3\/8,因此人数为:40 × 3\/8 = 15人。题目说明成绩在60分到79分之间的学生比80分及以上的多10人,所以该分数段人数为:15 + 10 = 25人。那么,成绩低于60分的学生人数为总人数减去前两个分数段的人数:40 - 15 - 25 = 5人。因此,正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:39:43","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5人","is_correct":1},{"id":"B","content":"8人","is_correct":0},{"id":"C","content":"10人","is_correct":0},{"id":"D","content":"12人","is_correct":0}]},{"id":1300,"subject":"数学","grade":"七年级","stage":"小学","type":"解答题","content":"某城市计划在一条东西走向的主干道旁建设一个矩形公园,公园的边界由四条道路围成。已知公园的东侧边界与主干道平行,且距离主干道120米。公园的北侧边界上有一盏路灯,其位置在平面直角坐标系中表示为点A(3, 8)。公园的南侧边界与北侧边界平行,且南北边界之间的距离为6米。公园的西侧边界是一条直线,经过点B(−2, 5),且与主干道垂直。现需在公园内部铺设一条从点A正下方地面点C(即点A在x轴上的投影)到点B的步行道,要求步行道为直线段。已知铺设步行道的成本为每米50元,且预算不得超过3000元。请判断该预算是否足够,并说明理由。(注:所有坐标单位均为百米,即1个单位代表100米)","answer":"1. 首先将坐标单位转换为实际距离(米):点A(3, 8)表示实际位置为(300, 800)米,点B(−2, 5)表示实际位置为(−200, 500)米。\n\n2. 点C是点A在x轴上的投影,因此其坐标为(300, 0)米。\n\n3. 计算步行道长度,即点C(300, 0)到点B(−200, 500)的距离:\n 使用距离公式:\n 距离 = √[(300 − (−200))² + (0 − 500)²]\n = √[(500)² + (−500)²]\n = √[250000 + 250000]\n = √500000\n = 500√2 ≈ 500 × 1.4142 ≈ 707.1米\n\n4. 计算铺设成本:\n 成本 = 707.1 × 50 ≈ 35355元\n\n5. 比较预算:\n 35355元 > 3000元,因此预算不足。\n\n答:该预算不足以铺设步行道,因为所需成本约为35355元,远超3000元的预算。","explanation":"本题综合考查了平面直角坐标系中点的坐标、距离公式、实数运算以及一元一次不等式的实际应用。解题关键在于理解坐标单位的实际意义(1单位=100米),正确确定点C的坐标,并运用勾股定理计算两点间距离。随后通过乘法运算得出总成本,并与预算进行比较,判断是否满足条件。题目融合了坐标几何、实数计算和不等式判断,具有较强的综合性,符合困难难度要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 10:47:48","updated_at":"2026-01-06 10:47:48","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":589,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级数学测验中,老师记录了某小组6名学生的成绩(单位:分)分别为:78、85、90、82、88、87。如果老师想计算这组数据的平均分,以下哪个选项是正确的?","answer":"B","explanation":"要计算这组数据的平均分,需要将所有分数相加,然后除以人数。计算过程如下:78 + 85 + 90 + 82 + 88 + 87 = 510。总人数为6人,因此平均分为510 ÷ 6 = 85(分)。所以正确答案是B选项。本题考查的是数据的收集、整理与描述中的平均数计算,属于七年级数学课程内容,难度简单,符合学生认知水平。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 20:24:40","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"84分","is_correct":0},{"id":"B","content":"85分","is_correct":1},{"id":"C","content":"86分","is_correct":0},{"id":"D","content":"87分","is_correct":0}]},{"id":14,"subject":"英语","grade":"初一","stage":"初中","type":"选择题","content":"What is the plural form of \"child\"?","answer":"B","explanation":"\"child\"的复数形式是\"children\"。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"childs","is_correct":0},{"id":"B","content":"children","is_correct":1},{"id":"C","content":"childes","is_correct":0},{"id":"D","content":"childies","is_correct":0}]},{"id":150,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"已知一个三角形的两边长分别为3厘米和7厘米,第三边的长度可能是多少厘米?","answer":"B","explanation":"根据三角形三边关系定理:任意两边之和大于第三边,任意两边之差小于第三边。设第三边为x,则有7 - 3 < x < 7 + 3,即4 < x < 10。选项中只有5厘米满足这个范围,因此正确答案是B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:35:13","updated_at":"2025-12-24 11:35:13","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3厘米","is_correct":0},{"id":"B","content":"5厘米","is_correct":1},{"id":"C","content":"10厘米","is_correct":0},{"id":"D","content":"11厘米","is_correct":0}]}]