初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":314,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在平面直角坐标系中描出点 A(3, 4) 和点 B(-2, 1),他想知道线段 AB 的中点坐标是多少。根据中点坐标公式,正确的结果是:","answer":"A","explanation":"根据平面直角坐标系中两点 A(x₁, y₁) 和 B(x₂, y₂) 的中点坐标公式:中点坐标为 ((x₁ + x₂)\/2, (y₁ + y₂)\/2)。将点 A(3, 4) 和点 B(-2, 1) 代入公式,横坐标为 (3 + (-2))\/2 = 1\/2 = 0.5,纵坐标为 (4 + 1)\/2 = 5\/2 = 2.5。因此,中点坐标为 (0.5, 2.5),对应选项 A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:36:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(0.5, 2.5)","is_correct":1},{"id":"B","content":"(1, 5)","is_correct":0},{"id":"C","content":"(2.5, 0.5)","is_correct":0},{"id":"D","content":"(5, 1)","is_correct":0}]},{"id":1064,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次环保活动中,某学生记录了连续5天每天回收的废纸重量(单位:千克)分别为:2.5、3、2.8、3.2、2.7。为了估算一个月(按30天计算)大约能回收多少千克废纸,他先计算了这5天的平均每天回收量,再用这个平均数乘以30。请问他计算出的月回收量估计值是___千克。","answer":"86.4","explanation":"首先计算5天回收废纸的总重量:2.5 + 3 + 2.8 + 3.2 + 2.7 = 14.2(千克)。然后求平均每天回收量:14.2 ÷ 5 = 2.84(千克\/天)。最后估算一个月(30天)的回收量:2.84 × 30 = 86.4(千克)。本题考查数据的收集、整理与描述中的平均数计算及其应用,属于简单难度,符合七年级数学课程内容。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:52:13","updated_at":"2026-01-06 08:52:13","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2016,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"在一次校园绿化活动中,某学生设计了一块等腰三角形花坛,已知其底边长为6米,两腰相等且长度为5米。若要在花坛内部铺设一条从顶点到底边中点的路径,则这条路径的长度为多少?","answer":"B","explanation":"本题考查勾股定理在等腰三角形中的应用。等腰三角形中,从顶点到底边中点的线段既是高,也是中线。因此,可将原三角形分为两个全等的直角三角形,每个直角三角形的斜边为腰长5米,底边为3米(因为底边6米被中点平分)。设路径(即高)为h,根据勾股定理:h² + 3² = 5²,即h² + 9 = 25,解得h² = 16,所以h = 4米。因此,这条路径的长度为4米,正确答案为B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 10:30:30","updated_at":"2026-01-09 10:30:30","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3米","is_correct":0},{"id":"B","content":"4米","is_correct":1},{"id":"C","content":"5米","is_correct":0},{"id":"D","content":"√34米","is_correct":0}]},{"id":552,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"在一次班级环保活动中,某学生记录了连续5天每天收集的废纸重量(单位:千克),分别为:3.5,4.2,3.8,4.0,3.7。为了更好地展示数据变化趋势,老师要求用折线图表示这些数据。如果将这5天的数据按顺序绘制在平面直角坐标系中,横轴表示天数(第1天到第5天),纵轴表示重量,那么下列哪个点的坐标不可能出现在这条折线图上?","answer":"C","explanation":"根据题意,第1天到第5天的废纸重量依次为:3.5,4.2,3.8,4.0,3.7千克。因此对应的坐标点应为:(1, 3.5),(2, 4.2),(3, 3.8),(4, 4.0),(5, 3.7)。选项A对应第2天,数据正确;选项B对应第3天,数据正确;选项D对应第5天,数据正确。而选项C中(4, 4.5)表示第4天收集了4.5千克,但实际记录为4.0千克,因此该点不可能出现在折线图上。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:09:52","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(2, 4.2)","is_correct":0},{"id":"B","content":"(3, 3.8)","is_correct":0},{"id":"C","content":"(4, 4.5)","is_correct":1},{"id":"D","content":"(5, 3.7)","is_correct":0}]},{"id":511,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"4题","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:16:19","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":925,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级数学测验成绩统计中,某学生将原始数据整理后绘制成频数分布直方图,发现成绩在80分到89分之间的人数占总人数的25%。如果全班共有40名学生,那么成绩在80分到89分之间的学生有___人。","answer":"10","explanation":"题目考查的是数据的收集、整理与描述中的百分比计算。已知总人数为40人,80分到89分的学生占25%,即求40的25%是多少。计算过程为:40 × 25% = 40 × 0.25 = 10。因此,该分数段的学生人数为10人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 02:48:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2150,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解方程时,将方程 2x + 5 = 13 的两边同时减去5,得到 2x = 8,然后再将两边同时除以2,得到 x = 4。这名学生使用的解题方法体现了等式的哪一条基本性质?","answer":"D","explanation":"该学生先对等式两边同时减去5,再同时除以2,整个过程体现了对等式两边进行相同运算时,等式依然成立这一基本性质。虽然选项B和C分别描述了其中一步所依据的性质,但整个解题过程综合体现了等式的基本性质:等式两边同时进行相同的运算(加、减、乘、除同一个数,除数不为零),等式仍然成立。因此,最全面且准确的答案是D。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"等式两边同时加上同一个数,等式仍然成立","is_correct":0},{"id":"B","content":"等式两边同时减去同一个数,等式仍然成立","is_correct":0},{"id":"C","content":"等式两边同时乘或除以同一个不为零的数,等式仍然成立","is_correct":0},{"id":"D","content":"等式两边同时进行相同的运算,等式仍然成立","is_correct":1}]},{"id":862,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生在整理班级同学的课外阅读情况时,发现喜欢阅读科幻小说的人数占总人数的30%,喜欢阅读历史书籍的人数比科幻小说的少10%,其余12人喜欢阅读其他类型书籍。那么该班级共有___名学生。","answer":"30","explanation":"设该班级共有x名学生。根据题意,喜欢科幻小说的人数为30%x = 0.3x,喜欢历史书籍的人数比科幻小说少10%,即少0.1x,因此喜欢历史书籍的人数为0.3x - 0.1x = 0.2x。其余12人喜欢其他类型书籍。根据总人数关系可得方程:0.3x + 0.2x + 12 = x,即0.5x + 12 = x。解这个一元一次方程:x - 0.5x = 12,0.5x = 12,x = 24 ÷ 0.5 = 30。因此,该班级共有30名学生。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:16:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":223,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个三角形的内角和是_空白处_度。","answer":"180","explanation":"根据三角形内角和定理,任意一个三角形的三个内角之和恒等于180度。这是七年级几何学习中的基本知识点,适用于所有类型的三角形,包括锐角三角形、直角三角形和钝角三角形。因此,空白处应填写180。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:40:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":693,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在整理班级同学的身高数据时,发现最高身高为172厘米,最矮身高为148厘米,则这组数据的极差是___厘米。","answer":"24","explanation":"极差是一组数据中最大值与最小值的差。题目中最高身高为172厘米,最矮身高为148厘米,因此极差为172 - 148 = 24厘米。本题考查的是数据的收集、整理与描述中的基本概念——极差,属于简单计算,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:37:23","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]