初中
数学
中等
来源: 教材例题
知识点: 初中数学
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π×(3²) = 16π - 9π = 7π(平方米)。因此正确答案是A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 15:47:00","updated_at":"2026-01-10 15:47:00","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"7π","is_correct":1},{"id":"B","content":"8π","is_correct":0},{"id":"C","content":"9π","is_correct":0},{"id":"D","content":"10π","is_correct":0}]},{"id":255,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在解方程时,将方程 3(x - 2) = 2x + 5 的括号展开后得到 3x - 6 = 2x + 5,然后移项合并同类项,最终解得 x = ___。","answer":"11","explanation":"首先将方程 3(x - 2) = 2x + 5 展开,得到 3x - 6 = 2x + 5。接着将含 x 的项移到等式左边,常数项移到右边:3x - 2x = 5 + 6,即 x = 11。因此,方程的解为 x = 11。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:54:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":610,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间时,记录了5位同学每周阅读的小时数分别为:3,5,4,6,2。如果老师要求每位同学的阅读时间都增加相同的整数小时,使得新的数据中位数变为5,那么每位同学至少需要增加多少小时?","answer":"A","explanation":"原始数据为:3,5,4,6,2。先将数据从小到大排序:2,3,4,5,6。当前中位数是中间的数,即4。设每位同学增加x小时(x为正整数),则新数据为:2+x,3+x,4+x,5+x,6+x。排序后仍为:2+x,3+x,4+x,5+x,6+x,中位数是4+x。要求中位数为5,即4 + x = 5,解得x = 1。因此,每位同学至少需要增加1小时。验证:增加1小时后数据为3,4,5,6,7,排序后中位数为5,符合条件。故正确答案为A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:36:13","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1","is_correct":1},{"id":"B","content":"2","is_correct":0},{"id":"C","content":"3","is_correct":0},{"id":"D","content":"4","is_correct":0}]},{"id":157,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"已知一个角的度数是60°,那么它的余角的度数是( )。","answer":"A","explanation":"余角是指两个角的和为90°。已知一个角是60°,则其余角为90° - 60° = 30°。因此正确答案是A。本题考查余角的基本概念,符合初一数学课程中关于角的学习内容。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:57:36","updated_at":"2025-12-24 11:57:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"30°","is_correct":0},{"id":"B","content":"60°","is_correct":0},{"id":"C","content":"90°","is_correct":0},{"id":"D","content":"120°","is_correct":0}]}]