初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":16,"subject":"历史","grade":"初一","stage":"初中","type":"选择题","content":"中国历史上第一个统一的中央集权制国家是?","answer":"B","explanation":"秦朝是中国历史上第一个统一的中央集权制国家,建立者是秦始皇嬴政。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"夏朝","is_correct":0},{"id":"B","content":"秦朝","is_correct":1},{"id":"C","content":"汉朝","is_correct":0},{"id":"D","content":"唐朝","is_correct":0}]},{"id":1882,"subject":"语文","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级同学对‘最喜欢的几何图形’的调查数据时,绘制了如下频数分布直方图(单位:人),其中横轴表示图形类别,纵轴表示人数。已知喜欢‘三角形’的人数比喜欢‘圆形’的多4人,喜欢‘正方形’的人数是喜欢‘平行四边形’的2倍,且喜欢‘梯形’和‘五边形’的人数之和为8人。若总调查人数为40人,且每个学生只选择一种图形,根据条形图显示:喜欢‘圆形’的人数为6人,喜欢‘正方形’的人数为10人,喜欢‘梯形’的人数为3人。那么,喜欢‘平行四边形’的人数是多少?","answer":"A","explanation":"根据题意,已知喜欢‘圆形’的人数为6人,则喜欢‘三角形’的人数为6 + 4 = 10人;喜欢‘正方形’的人数为10人,是喜欢‘平行四边形’的2倍,因此喜欢‘平行四边形’的人数为10 ÷ 2 = 5人;喜欢‘梯形’的人数为3人,喜欢‘五边形’的人数为8 - 3 = 5人。验证总人数:圆形6 + 三角形10 + 正方形10 + 平行四边形5 + 梯形3 + 五边形5 = 39人,与总人数40人不符?但注意题目中‘梯形和五边形之和为8人’,已给出梯形为3人,故五边形为5人,合计8人,正确。再核对总数:6+10+10+5+3+5=39,仍少1人。但题目明确指出‘总调查人数为40人’,说明可能存在一个未列出的图形类别或数据误差。然而,题干强调‘每个学生只选择一种图形’,且所有类别均已覆盖。重新审视:题目说‘根据条形图显示’给出部分数据,其余通过条件推导。关键在于‘喜欢正方形的是平行四边形的2倍’,若正方形为10人,则平行四边形必为5人,此为唯一解。其余数据均吻合,总数39与40的差异可能源于题设中隐含一个‘其他’类别或笔误,但根据逻辑推理,唯一满足所有条件的是平行四边形为5人。因此正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:55:13","updated_at":"2026-01-07 09:55:13","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5人","is_correct":1},{"id":"B","content":"6人","is_correct":0},{"id":"C","content":"7人","is_correct":0},{"id":"D","content":"8人","is_correct":0}]},{"id":500,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生调查了班级同学每天使用手机的时间(单位:分钟),并将数据整理如下:15,20,25,30,35,40,45,50,55,60。如果去掉一个最大值和一个最小值后,剩余数据的平均数是多少?","answer":"A","explanation":"首先确定原始数据中的最大值是60,最小值是15。去掉这两个值后,剩余的数据为:20,25,30,35,40,45,50,55,共8个数。计算这些数的和:20 + 25 + 30 + 35 + 40 + 45 + 50 + 55 = 300。然后用总和除以数据个数:300 ÷ 8 = 37.5。因此,剩余数据的平均数是37.5,正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:09:45","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"37.5","is_correct":1},{"id":"B","content":"40","is_correct":0},{"id":"C","content":"42.5","is_correct":0},{"id":"D","content":"45","is_correct":0}]},{"id":495,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间数据时,发现一周内每天阅读时间(单位:分钟)分别为:30、45、0、60、35、50、40。如果去掉一个最低值和一个最高值后,剩余数据的平均数是多少?","answer":"C","explanation":"首先将数据按从小到大排列:0、30、35、40、45、50、60。最低值是0,最高值是60,去掉这两个值后,剩余数据为:30、35、40、45、50。计算这五个数的平均数:(30 + 35 + 40 + 45 + 50) ÷ 5 = 200 ÷ 5 = 42。因此,正确答案是C。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:06:51","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"40","is_correct":0},{"id":"B","content":"41","is_correct":0},{"id":"C","content":"42","is_correct":1},{"id":"D","content":"43","is_correct":0}]},{"id":1081,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了废旧纸张和塑料瓶共30件。已知每张废旧纸张可兑换0.2元,每个塑料瓶可兑换0.5元,该学生共获得10.8元。若设废旧纸张有x张,则可列出一元一次方程为:____ + 0.5(30 - x) = 10.8","answer":"0.2x","explanation":"题目中已知废旧纸张和塑料瓶总数为30件,设废旧纸张有x张,则塑料瓶有(30 - x)个。每张废旧纸张兑换0.2元,因此x张可兑换0.2x元;每个塑料瓶兑换0.5元,(30 - x)个可兑换0.5(30 - x)元。总金额为10.8元,所以方程为:0.2x + 0.5(30 - x) = 10.8。空白处应填写的是废旧纸张兑换的金额部分,即0.2x。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:54:09","updated_at":"2026-01-06 08:54:09","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":549,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,成绩分布如下表所示。已知成绩在80分及以上的学生占总人数的40%,成绩在60分到79分之间的学生比成绩在60分以下的学生多10人,且全班共有50名学生。那么,成绩在60分以下的学生有多少人?","answer":"A","explanation":"设成绩在60分以下的学生有x人,则成绩在60分到79分之间的学生有(x + 10)人。根据题意,成绩在80分及以上的学生占总人数的40%,即50 × 40% = 20人。全班总人数为50人,因此可以列出方程:x + (x + 10) + 20 = 50。化简得:2x + 30 = 50,解得2x = 20,x = 10。所以,成绩在60分以下的学生有10人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:08:26","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10人","is_correct":1},{"id":"B","content":"15人","is_correct":0},{"id":"C","content":"20人","is_correct":0},{"id":"D","content":"25人","is_correct":0}]},{"id":242,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生计算一个数的相反数时,将原数乘以 -1,得到的结果是 7,那么这个数是____。","answer":"-7","explanation":"根据相反数的定义,一个数的相反数等于这个数乘以 -1。题目中说乘以 -1 后得到 7,说明原数 × (-1) = 7。解这个等式可得:原数 = 7 ÷ (-1) = -7。因此,这个数是 -7。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:42:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":805,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在整理班级同学的课外阅读情况时,收集了每位同学每月阅读的书籍数量,并将数据按从小到大的顺序排列。已知这组数据的中位数是4,且数据个数为奇数。如果去掉最大的一个数据后,新的中位数变为3.5,那么原数据中最少有多少个数据?____","answer":"7","explanation":"设原数据有n个,且n为奇数。中位数为第(n+1)\/2个数,已知为4。去掉最大的一个数据后,剩下n-1个数据(偶数个),中位数为中间两个数的平均数,即第(n-1)\/2个和第(n+1)\/2个数据的平均值为3.5。由于原数据有序,去掉最大值后,中间两个数应分别为3和4(因为(3+4)\/2=3.5)。为了使这种情况成立,原数据中第(n+1)\/2个数必须是4,且其前一个数为3。当n=7时,原数据第4个数为4,去掉最大值后剩下6个数,第3和第4个数分别为3和4,满足新中位数为3.5。若n<7(如n=5),则无法满足去掉最大值后中间两数为3和4的条件。因此原数据最少有7个。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:22:41","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1077,"subject":"数学","grade":"七年级","stage":"小学","type":"填空题","content":"在一次班级环保活动中,某学生收集了若干节废旧电池。若每5节电池装一盒,则最后剩下3节;若每7节电池装一盒,则刚好装完。该学生至少收集了___节废旧电池。","answer":"28","explanation":"设该学生收集的电池总数为x节。根据题意,x除以5余3,即x ≡ 3 (mod 5);同时x能被7整除,即x ≡ 0 (mod 7)。我们寻找满足这两个条件的最小正整数。列出7的倍数:7, 14, 21, 28, 35…,检查哪些数除以5余3。7÷5=1余2,14÷5=2余4,21÷5=4余1,28÷5=5余3,满足条件。因此最小的x是28。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:53:45","updated_at":"2026-01-06 08:53:45","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":686,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了若干千克废旧纸张。如果将这些纸张平均分给5个小组,每组可得12千克;后来又有3个小组加入,现在要将这些纸张重新平均分给所有小组,那么每个小组分到的纸张是___千克。","answer":"7.5","explanation":"首先根据题意,原来有5个小组,每组12千克,所以总纸张重量为 5 × 12 = 60 千克。后来增加了3个小组,总小组数变为 5 + 3 = 8 个。将60千克纸张平均分给8个小组,每个小组分到 60 ÷ 8 = 7.5 千克。本题考查了一元一次方程的实际应用和整数的除法运算,属于简单难度,符合七年级学生对有理数和一元一次方程知识点的掌握水平。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:33:25","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]