初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":661,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级环保活动中,某学生收集了若干节废旧电池。如果他将收集到的电池数量增加5节后,总数恰好是原来数量的2倍。那么他原来收集了___节电池。","answer":"5","explanation":"设该学生原来收集了x节电池。根据题意,增加5节后总数为x + 5,而这个数量等于原来数量的2倍,即2x。因此可以列出方程:x + 5 = 2x。解这个一元一次方程,将x移到右边得5 = 2x - x,即5 = x。所以原来收集了5节电池。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:15:41","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1810,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某公园计划修建一个等腰三角形花坛,设计要求其底边长为6米,两腰相等且每腰长为5米。施工前需要计算该花坛的高,以便准备支撑材料。请问这个等腰三角形花坛的高是多少米?","answer":"B","explanation":"此题考查勾股定理在等腰三角形中的应用。等腰三角形底边上的高将底边平分为两段,每段长度为3米。由此可构造一个直角三角形,其中一条直角边为3米(底边的一半),斜边为5米(腰长),所求高为另一条直角边。根据勾股定理:高² = 5² - 3² = 25 - 9 = 16,因此高 = √16 = 4米。故正确答案为B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 16:18:43","updated_at":"2026-01-06 16:18:43","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3米","is_correct":0},{"id":"B","content":"4米","is_correct":1},{"id":"C","content":"5米","is_correct":0},{"id":"D","content":"6米","is_correct":0}]},{"id":786,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书角统计中,某学生记录了上周同学们借阅图书的天数,其中借阅3天的人数占总人数的40%,借阅5天的人数占总人数的60%。如果总人数为25人,那么这些同学上周平均每人借阅图书的天数是____天。","answer":"4.2","explanation":"首先计算借阅3天的人数:25 × 40% = 10人;借阅5天的人数:25 × 60% = 15人。然后计算总借阅天数:10 × 3 + 15 × 5 = 30 + 75 = 105天。最后求平均数:105 ÷ 25 = 4.2天。因此,平均每人借阅图书的天数是4.2天。本题考查了数据的收集、整理与描述中的加权平均数计算,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:06:04","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2301,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"在一次班级数学测验中,某学生记录了5名同学完成一次函数应用题所用的时间(单位:分钟),分别为:8、10、12、10、15。这组数据的中位数和众数分别是多少?","answer":"A","explanation":"首先将数据从小到大排列:8、10、10、12、15。共有5个数据,奇数个,因此中位数是中间的那个数,即第3个数,为10。众数是出现次数最多的数,10出现了两次,其余数各出现一次,因此众数是10。所以正确答案是A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 10:44:00","updated_at":"2026-01-10 10:44:00","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"中位数是10,众数是10","is_correct":1},{"id":"B","content":"中位数是12,众数是10","is_correct":0},{"id":"C","content":"中位数是10,众数是12","is_correct":0},{"id":"D","content":"中位数是11,众数是10","is_correct":0}]},{"id":251,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在解方程 3(x - 2) + 5 = 2x + 7 时,第一步将等式左边展开得到 3x - 6 + 5,合并同类项后为 3x - 1;第二步将方程写成 3x - 1 = 2x + 7;第三步将 2x 移到左边,-1 移到右边,得到 3x - 2x = 7 + 1;第四步解得 x = ___。","answer":"8","explanation":"根据题目描述的解方程步骤:第一步展开括号正确,3(x - 2) = 3x - 6,再加5得 3x - 1;第二步方程为 3x - 1 = 2x + 7;第三步移项,将含x的项移到左边,常数项移到右边,即 3x - 2x = 7 + 1;第四步计算得 x = 8。此过程符合解一元一次方程的基本步骤,移项变号规则应用正确,最终结果为8。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:54:13","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":679,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级数学测验成绩统计中,某学生发现自己的成绩比全班的平均分高6分。如果全班共有30人,所有人的成绩总和为2400分,那么这名学生的成绩是____分。","answer":"86","explanation":"首先根据全班30人、总分2400分,可以求出全班平均分为:2400 ÷ 30 = 80(分)。题目说明该学生的成绩比平均分高6分,因此他的成绩为:80 + 6 = 86(分)。本题考查了数据的收集、整理与描述中的平均数计算,并结合有理数的加减运算,难度为简单,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:28:41","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":638,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级在一次数学测验中,收集了30名学生的成绩,并将成绩分为5个分数段进行统计。已知前四个分数段的人数分别为4、7、9、6,则第五个分数段的人数是多少?","answer":"B","explanation":"题目考查的是数据的收集与整理。总人数为30人,前四个分数段的人数分别为4、7、9、6。将这些人数相加:4 + 7 + 9 + 6 = 26。因此,第五个分数段的人数为30 - 26 = 4。所以正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:05:16","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3","is_correct":0},{"id":"B","content":"4","is_correct":1},{"id":"C","content":"5","is_correct":0},{"id":"D","content":"6","is_correct":0}]},{"id":206,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个三角形的三个内角分别是50度、60度和_空白处_度。","answer":"70","explanation":"三角形的内角和恒等于180度。已知两个角分别是50度和60度,将这两个角相加得到50 + 60 = 110度。用180度减去110度,得到第三个角的度数为180 - 110 = 70度。因此,空白处应填写70。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:39:36","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2758,"subject":"历史","grade":"七年级","stage":"初中","type":"选择题","content":"考古学家在河南安阳发现了一处大型商代遗址,出土了大量刻有文字的龟甲和兽骨。这些文字主要用于记录商王占卜的内容,对研究商朝历史具有重要价值。这种文字被称为:","answer":"A","explanation":"题干中提到‘刻有文字的龟甲和兽骨’以及‘用于记录商王占卜的内容’,这是甲骨文的典型特征。甲骨文是商朝时期刻在龟甲和兽骨上的文字,主要用于占卜记事,是中国已发现的古代文字中时代最早、体系较为完整的文字。金文主要铸刻在青铜器上,盛行于西周;小篆是秦朝统一后的标准字体;隶书则流行于汉代。因此,根据出土文物的材质和用途,正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-12 10:39:39","updated_at":"2026-01-12 10:39:39","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"甲骨文","is_correct":1},{"id":"B","content":"金文","is_correct":0},{"id":"C","content":"小篆","is_correct":0},{"id":"D","content":"隶书","is_correct":0}]},{"id":614,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,统计了每位同学每周阅读课外书的小时数,并将数据分为5组:0-2小时,2-4小时,4-6小时,6-8小时,8小时以上。已知阅读时间在4-6小时的人数最多,共12人;阅读时间在0-2小时的人数最少,只有3人;其他三组人数分别为5人、8人和7人。请问该班级共有多少名学生参与了这项统计?","answer":"C","explanation":"本题考查数据的收集与整理。根据题意,将各组人数相加即可得到总人数:0-2小时有3人,2-4小时有5人,4-6小时有12人,6-8小时有8人,8小时以上有7人。计算总和:3 + 5 + 12 + 8 + 7 = 35。因此,该班级共有35名学生参与了统计。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:39:31","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"30人","is_correct":0},{"id":"B","content":"33人","is_correct":0},{"id":"C","content":"35人","is_correct":1},{"id":"D","content":"38人","is_correct":0}]}]