初中
数学
中等
来源: 教材例题
知识点: 初中数学
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20% - 40% = 40%,对应人数为 60 × 40% = 24人。因此,成绩低于70分的学生有24人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 20:28:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"18人","is_correct":0},{"id":"B","content":"24人","is_correct":1},{"id":"C","content":"30人","is_correct":0},{"id":"D","content":"36人","is_correct":0}]},{"id":2545,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"某圆形花坛的半径为6米,现计划在花坛中心安装一个旋转喷头,其喷洒范围为一个圆心角为120°的扇形区域。若喷头随机旋转,且每次喷洒的起始角度在0°到360°之间均匀分布,则某学生站在距离花坛中心4米的位置时,被水喷洒到的概率是多少?","answer":"A","explanation":"该问题考查概率初步与圆的结合应用。喷头喷洒范围为120°的扇形,而整个圆周为360°。由于喷头起始角度在0°到360°之间均匀随机分布,因此喷洒区域覆盖某一固定方向(如某学生所在位置)的概率等于扇形圆心角占整个圆周的比例。学生位于花坛内部(距离中心4米 < 半径6米),始终处于喷洒半径范围内,因此是否被喷洒仅取决于角度是否落在120°的扇形区域内。故概率为120° \/ 360° = 1\/3。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 17:00:10","updated_at":"2026-01-10 17:00:10","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1\/3","is_correct":1},{"id":"B","content":"1\/4","is_correct":0},{"id":"C","content":"1\/6","is_correct":0},{"id":"D","content":"1\/2","is_correct":0}]},{"id":1796,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某校七年级组织学生参加数学兴趣小组活动,报名参加A、B两个小组的人数共45人。已知参加A组的人数比B组人数的2倍少3人。设参加B组的人数为x,则下列方程正确的是:","answer":"A","explanation":"根据题意,设参加B组的人数为x,则参加A组的人数比B组的2倍少3人,即A组人数为2x - 3。两组总人数为45人,因此可列出方程:x + (2x - 3) = 45。选项A正确。选项B错误,因为A组是比2倍少3,不是多3;选项C只考虑了A组人数等于45,忽略了总人数包含两组;选项D虽然变形后等价,但表达方式不规范,未明确体现A组人数的代数式,不符合设未知数列方程的标准形式。因此,最准确且符合题意的方程是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-06 16:12:21","updated_at":"2026-01-06 16:12:21","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"x + (2x - 3) = 45","is_correct":1},{"id":"B","content":"x + (2x + 3) = 45","is_correct":0},{"id":"C","content":"2x - 3 = 45","is_correct":0},{"id":"D","content":"x + 2x = 45 - 3","is_correct":0}]},{"id":851,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在绘制班级同学最喜爱的课外活动统计图时,将数据整理成如下表格:阅读占20%,运动占35%,音乐占15%,绘画占___%,其余为其他活动。已知喜欢绘画的人数比喜欢音乐的人数多6人,且班级总人数为60人,那么绘画所占的百分比是____。","answer":"25","explanation":"首先,根据题意,班级总人数为60人。喜欢音乐的人占15%,即 60 × 15% = 9 人。喜欢绘画的人数比音乐多6人,所以绘画人数为 9 + 6 = 15 人。那么绘画所占的百分比为 (15 ÷ 60) × 100% = 25%。因此,空白处应填写25。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:04:52","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":511,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"4题","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:16:19","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":696,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书角整理活动中,某学生统计了同学们捐赠的书籍数量。他发现,如果每人捐赠3本书,则总共多出12本;如果每人捐赠4本书,则刚好分完。设该班有x名学生,则可列出一元一次方程为:___","answer":"3x + 12 = 4x","explanation":"根据题意,第一种情况:每人捐3本,共捐出3x本,多出12本,说明总书数为3x + 12;第二种情况:每人捐4本,刚好分完,说明总书数也是4x。由于总书数不变,因此可列方程3x + 12 = 4x。本题考查一元一次方程的实际应用,通过理解数量关系列出等量关系式。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:38:59","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]